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 AN6535
4-pin Negative Adjustable Voltage Regulator
s Overview
The AN6535 is a monolithic 4-pin negative adjustable voltage regulator. With an external resistor, it provides any stabilized output voltages between -5V and-30V, and is optimum for the power circuits with a current capacitance of up to 0.5A. With various protective circuits built in, it has high reliability and is provided in a 4-lead SIL plastic package.
9.6 - 0.1 o 3.1
4.0
+ 0.5
Unit:mm
12.5max.
0.70.2
9.0min.
3-1.0 1.8
2.0
0.50.1 1.5 1.3
s Features
* Wide range of output voltages:VO= -5 to -30V * Interal thermal overload protection * Interal short-circuit protection * Output transistor safe area compensation
2.3 2.3 2.3
3.3max.
4-pin SIL Plastic Package with Fin (SSIP004-P-0000)
s Block Diagram
Start Circuit
Ref. Voltage
+ Error Amp. -
Output Pass Tr.
Thermal Protection Rsc Short Circuit Protection
1 Common
2 Input
3 Output
4 Control
s Absolute Maximum Ratings (Ta=25C)
Parameter Supply voltage Supply current Power dissipation Operating ambient temperature Storage Symbol VCC ICC *1 PD Topr Tstg Rating -40 1 7.5 -20 to +80 -55 to +150 Unit V A W C C
*1 The internal circuit is provided with a current limiting circuit. *2 Maximum power dissipation value when there is no heat sink (The value varies depending on the external heat dissipation state)
s Electrical Characteristics (Ta=25C)
Parameter Output voltage tolerance Symbol VO Condition VI=VO-3V to VO-15V, IO=5 to 350mA, Tj=25C VO=-5V, IO=200mA, VI=-7.5 to -25V, Tj=25C VO=-18V, IO=5mA, VI=-21 to -33V, Tj=25C VO=-18V, IO=200mA, VI=-21 to -25V, Tj=25C IO=5 to 500mA Tj=25C Tj=25C Tj=25C VI=-8 to -18V, VO=-5V, f=120Hz VO=-5V, f=10Hz to 100kHz IO=500mA, Tj=25C VI=-35V, VO=-5V, Tj=25C VO=-5V, Tj=25C VO=-5V IO=5mA Tj=25C Tj=-20 to +25C Tj=25 to 150C -3.12 0.4 VO=-5V, VI=-12V VO=-18V, VI=-25V 1.5 min typ max 4 1 0.75 0.67 1 3 3 60 40 1.1 100 0.8 0.2 - 0.3 -3 -2.88 600 1.4 Unit % % % % % mA A dB V V mA A mV/C V
Line regulation
REGIN
Load regulation Bias current Control pin current Ripple rejection ratio Output noise voltage Minimum input/output voltage difference Short-circuit current Peak output current Output voltage temperatrue coefficient Control pin voltage
REGL IBias Icont RR Vno VDIF (min.) IOS IOP VO/Ta Vcont
Note 1) The specified condition Tj=25C means that the test should be conducted with each test time reduced (within 10 ms) so that the drift in the characteristic value due to a temperature rise at chip junction can be ignored. Note 2) Unless otherwise specified, VI=-10V, VO=-5V, IO=350mA, CI=2F, and CO=1F
s Characteristics Curve
PD -Ta
10 (1) (2) (3) (4) (1) 6 (2) 4 (3) 2 (4) 0 0 20 40 60 80 100 120 140 160 0 Te=Ta With a 10C/W heat sink With a 20C/W heat sink Without heat sink 1.6 1.4
IOP -VDIF
Tj=25C
VDIF (min.) -Tj
Min. I/O Voltage Difference VDIF (min.) (V)
1.4
Power Dissipation PD (W)
8
Peak Output Current IOP (A)
1.2 IO =
IO =
1.2 1.0 0.8 0.6 0.4 0.2
1.0
20
I=500mA 0m A
10
IO=
0.8
0m A 10m A
0.6
0.4 -50 0 50 100 150
10
20
30
Ambient Temperature Ta (C)
I/O Voltage Difference VDIF (V)
Juction Temperature Tj (C)
RR- f
120 IO=100mA
Line Transient Response
VO=5V -15
Ripple Rejection Ratio RR (dB)
100
Output Voltage Fluctuation (mV)
80
-10
60
-5 10
40
0
20
-10
0 10 100 1k 10k 100k
-20 0 2 4 6 8 10
Frequency f (Hz)
Time t (s)
Load Transient Response
Load Current IO (A) Output Voltage VO (V)
-6 1
Output Current Limit
104 VI=-10V VO=-5V IO=20mA CO=1F Ta=25C 103
Input Voltage V (V)
-20
ZO - f
0.5
-4
Output Voltage Fluctuation (V)
0 1
-3
VI=-10V VO=-5V Tj=25C
Output Impedance ZO (m)
0.4 0.6 0.8 1.0 1.2
-5
0
-2
102
-1
-1
-2
0 0 10 20 30 40 50 0 0.2
10 10 100 1k 10k 100k 1M
Time t (s)
Output Current IO (A)
Frequency f (Hz)
s Basic Regulator Circuit
+VI 2 3 R2 Vcont - + +VO
Input Output
CI : 2F
- +
Control 4 Common 1
R1
s Application Circuits
(1) Current Boost Circuit
VI R3 6 2 IR 2F - + IP Input Output 3 4 3k IO VO R2 - R1 + 1F IR - 2F + R3 6 Q2 2 IP Input Output 3 4 3k R1 VI Q1 RSC Ie2 IO VO R2 - 1F + Ie1
CO
1F
AN6535
R1+R2 R1 (Vcont 3V, R1=3k) CI : Necessary when the VI line is long. CO : Improves the transient response. VO=Vcont
(2) Current Boost Circuit (With Current Limiting Circuit)
Q1
AN6535
Control Common 1
AN6535
Control Common 1
R3=
VBE (Q1) * ( +1) IP - IO
VBE (Q1) RSC= I e1 (max.) R3= VBE (Q1)+Ie1RSC IO - Ie1 VBE (Q1)+BE (Q1) R3
Ie1 (max.)=IP (max.) -


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